There are three ants at the three corners of a regular
triangle. Each ant starts moving on a straight line toward
another, randomly chosen corner. What is the probability
that none of the ants collide?
2 comments:
Anonymous said...
25%. From the ant's perspective each can go left or right. There are 8 poss combinations - LLL, LLR, LRL, RLL, LRR, RLR, RRL, and RRR. You can also work that out by raising 2 (the number of choices) to the power of 3 (the number of choosers) = 2 x 2 x 2 = 8. In only 2 of these cases (LLL and RRR will there be no collisions, so 2 / 8 = 0.25
Secret Squïrrel
March 9, 2008 6:34 AM
Neeraj said...
There are two directions tomove for each ant
Thus total 2x2x2 =8 movements in different directions
out of these only two result in non - collisions of any of the ant - either all clockwise or all counter clockwise
Thus rest 6 result in at leaat 1 collission.
Thus probablility of non collision = 2/8=1/4=0.25
Reference : http://puzzles4you.blogspot.com/2008/03/three-ants.html
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